Question

An aeroplane travels on the runway for 20s with an acceleration of 3.2 m/s2 before taking off. how much stance would it have covered on the runway.​

Answer 1

$\sf \pmb{Answer :}$ \sf \:

The aeroplane would have covered 1440 m on the runway.

Explanation:

Given :-

An aeroplane taxies on the runway for 30 s with an acceleration of 3.2 m/s² before taking off.

To find :-

How much distance would it have covered on the runway ?

Solution :-

Formula used :

t = time = 30 s

a = acceleration = 3.2 m/s²

u = initial velocity = 0 m/s

{\boxed{\sf{S=ut+\dfrac{1}{2}at^2}}}

[put values]\mapsto\sf{S=0\times\:t+\dfrac{1}{2}\times\:3.2\times\:(30)^2}

\mapsto\sf{S=0+(16\times\:3\times\:30)}

\mapsto\sf{S=1440}

Therefore, it would have covered 1440 m on the runway.

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Some formulas :

\sf{v=u+at}

\sf{v^2=u^2+2as}

\sf{s_n=u+\dfrac{1}{2}a(2n-1)}