An aeroplane travels with 900kmph half the time and with 760kmph half the time if the total trip is 4 hours. Find the average speed.
Answers
Answer:
Speed for half time i.e.2 hours = 900 km/ph
Speed for another half time i.e.2 hours= 760km/ph
Total time=4 hours
Average Speed = Total distance / Total Time
We need to find Distance 's'
For first half time s = speed x time
= 900 x 2
= 1800 km
For second half time s= 760 x 2
=1520
Total s = 1800+1520
=3320km
Average Speed = 3320/4
= 830 km/ph
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Answer:
The average speed = 830 kmph
Explanation:
Speed of first half time = 900 kmph
Speed of second half time = 760 kmph
Total time = 4 hrs.
To get the average speed first find the distance
So,
Case A
distance = speed × time
⇒ 900 kmph × 2 hrs
⇒ 1800 km ----------------------(A)
Case B
distance = speed × time
⇒ 760 kmph × 2 hrs
⇒ 1520 km ----------------------(B)
Adding (A) and (B)
1800 km + 1520 km = 3320 km
Total distance = 3320 km
Now, find the average speed
average speed = total distance travelled / total time taken
⇒ 3320 / 4
⇒ 830 kmph
Therefore,
The average speed = 830 kmph