Question

an aeroplane when flying at a height of 4000m from the ground posses vertically above another aeroplane at an instant when the angles of elevation of the two planes from the same point on the ground are 60° and 45°reptly . find the vertical distance between the aeroplane at the instant?​

Answer 1

Answer:-

The Distance Between The Two Aeroplanes $\bf = 400\bigg(1-\dfrac{1}{\sqrt{3}}\bigg)m.$

Explanation:-

(See The Attachments (2) For Explanation).

More Related Information:-

$\boxed{\begin{minipage}{7 cm}Trigonometric Identities \\ \\ \sin^2\theta + \cos^2\theta=1 \\ \\1+\tan^2\theta = \sec^2\theta \\ \\1+\cot^2\theta = \text{cosec}^2 \, \theta \end{minipage}}$