Question

an aeroplane when flying at aheight of 4000m from ground passes vertically above another aeroplane at an instant when the angle of elevation of 2 planes from the same point on ground are 60 and 45 respectively . find the distance between planes at that instant .

Answer 1

(4000+x)/d=tan60
4000/d=tan45=1
d=4000
now put d and find distance between plane
I.e.x=4000 (root3-1)