an aeroplane which is flying at a height of 3125 m passes above another plane when the angle of elevation of two plane are 30° and 60°. Find the distance between the two planes
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Answer:
6250
Step-by-step explanation:
We know that \[BD=BC+CD\]. Thus, we have \[9375=3125+CD\]. So, we have \[CD=9375-3125=6250m\]. Hence, the distance between two planes is 6250m.
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