Question

An aeroplane with wing span 50 m is flying horizontally with a speed of 360 km/hr over a place where the vertical component of the earth's magnetic field is 2x10 wb/m. The potential difference between the tips of the wings would be

Answer 1

Answer:

The potential difference will be 1000000 V

Explanation:

According to the problem the wing span of the plane is 50 m

the speed of the plane ,u is 360 km/hr= 360×1000/3600=100m/s

The magnetic field is 2 x 10 wb/m

Now if we use the expression for induced Emf

e=Bul

∴e=2×10×100×50

=1000000V

Hence the potential difference between the tips of the wings would be 1000000V

Answer 2

Answer:1.0V

Explanation:GIVEN MAGNETIC FIELD=2x10^-4

Wing span length is =50m

And speed is 360Km/hr

Convert speed to m\s 360x10^-4=100m/s

Now applying BLV

BLV=(2x10^-4)x100x50

=10000x10^-4=1.0V