An aerostat of mass m starts coming down with a constant acceleration ω. Determine the ballast mass to be dumped for the aerostat to reach
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Let R be the constant upward thurst on the aerostat of mass m, coming down with a constant acceleration w. Applying Newton's second law of motion for the aerostat in projection form
Now, if Δm be the mass, to be dumped, then using the Eq. Fy=mwy
Now, if Δm be the mass, to be dumped, then using the Eq. Fy=mwy
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Answer:
X = 2mw/g+w
Explanation:
Let R be the upthrust acting on the aerostat,
Let X be the ballast mass to be dumped,
Since the acceleration is acting downwards,
=>mg - R = mw
=> R = mg - mw ••• (1)
After removing the ballast mass, acceleration acts upwards,
=>R - (m - X)g = (m - X)w
=>R - mg + Xg = mw - Xw
=>R + Xg + Xw = mw + mg
=>mg - mw + X(g+w) = mw + mg
=>X(g+w) = 2mw
=>X = 2mw/g+w ••• (ans)
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