Question

An agricultural field is in the form of a rectangle of length 20 m and width 14 m. A pit 6 m long, 3 m wide and 2.5 m deep is dug in a corner of the field and the earth taken out of the pit is spread uniformly over the remaining area of the field. Find the extent to which the level of the field has been raised.​

Answer 1

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$Volume \: of \: pit = 6 \times 3 \times 2.5 = 45 {m}^{3}$

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$\implies\:$Volume of earth taken out = volume of earth spread in the remaining field

$\implies\: 45 = {(20 \times 14) - 6 \times 3 } \times h$

$= > 45 = 262 \times h$

$= > h = \frac{45 \times {10}^{6} }{262 \times {10}^{4} }$

$= > 17.18cm$

$\boxed {h=17.18cm}$

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Answer 2

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Refer to attachment..

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