Question

An agricultural field is in the form of a rectangle of length 20m and width 14m. A pit 6m long, 3m wide and 2.5m deep is dug in the corner of the field and the earth taken out of the pit is spread uniformly over the remaining area of the field. Find the extent to which the level of the field has been raised.

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Answer 1

The volume of the soil taken out from the pit = 6 x 3 x 2.5 m3 = 45 m3

Now, The surface area of the remaining field is = (20 x 14) - (6 x 3) = 280 - 18 = 262 m2

When the soil taken out is spread uniformly over the remaining field, height increased will be

h = 45 m3/ 262 m2

=> h = (45/262) m = (4500/262) cm = 17.17557 cm

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Answer 2

Answer:

The volume of the soil taken out from the pit = 6 x 3 x 2.5 m3 = 45 m3

Now, The surface area of the remaining field is = (20 x 14) - (6 x 3) = 280 - 18 = 262 m2

When the soil taken out is spread uniformly over the remaining field, height increased will be

h = 45 m3/ 262 m2

=> h = (45/262) m = (4500/262) cm = 17.17557 cm