Physics, asked by gengajeomkar, 5 months ago

An air bubble of radius 0.2 mm is situated just below the water surface. Calculate the
gauge pressure. Surface tension of water is 7.2 ×10-2N/m.

Answers

Answered by tapaskumahhr86886
0

Answer:

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Answered by abhilash7995
0

Answer:

Given: Radius of bubble = 0.2mm or 0.2×(10) −3Nm

Surface tension of water = 7.2×(10) −2 N/m

We know that, excess pressure inside a air bubble in a liquid is given by

Where,

t = surface tension of liquid

r = radius of bubble

Thus,

Excess pressure =

0.2×(10) −3/2×7.2×(10) −2

=

2× 72/2×(10) −1

=72×(10) 1

=720n/m

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