Physics, asked by lokhandeshubham522, 4 months ago

An air bubble of radius 0.2 mm is situated
just below the water surface. Calculate
the gauge pressure. Surface tension of
water = 7.2 x 10-2 N/m.​

Answers

Answered by Lohithreddy162008
1

Answer:

720

Explanation:

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Attachments:
Answered by ItzMissKomal
1

Answer:

Given: Radius of bubble = 0.2mm or 0.2×(10)

−3

m

Surface tension of water = 7.2×(10)

−2

N/m

We know that, excess pressure inside a air bubble in a liquid is given by

Where,

t = surface tension of liquid

r = radius of bubble

Thus,

Excess pressure =

0.2×(10)

−3

2×7.2×(10)

−2

=

2×(10)

−1

2×72

=72×(10)

1

=720n/m

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