Question

An air bubble of volume 3mL is released at the bottom of a water tank of height 20 feet. Calculate the volume of the bubble when it reaches the surface of water. (Atmospheric pressure 75 cm Hg). Please write the formula also.​

Answer 1

Answer:

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Explanation:

We can assume that the process is isothermal because the temperature of the surrounding remains constant

So, by applying Boyle’s law

P

s

V

s

=P

d

V

d

.....(I)

Where, s = surface of water

d = depth

Given that,

Depth of lake =h

Volume V

s

=3V

d

Now,

P

s

=75cmHg

P

d

=75+

10

h

Now, put the value of equation(I)

75×3=75+

10

h

225−75=

10

h

h=1500cm

h=15m

Hence, the depth of lake is 15 m