Question

An air core solenoid has 1000 turns and is 1 metre long its cross-sectional area is 10 cm square it's self inductance is

Answer 1

The self inductance of the solenoid is 1.25 mH.

Explanation:

Given that,

Number of turns, n = 1000

Length of the solenoid, l = 1 m

Area of cross section of the solenoid, $A=10\ cm^2=0.001\ m^2$

We need to find the self inductance of the solenoid. It is given by :

$L=\dfrac{\mu_on^2A}{l}$

$L=\dfrac{4\pi \times 10^{-7}\times (1000)^2\times 0.001}{1}$

L = 0.00125 H

or

L = 1.25 mH

So, the self inductance of the solenoid is 1.25 mH. Hence, this is the required solution.

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