Question

An air craft executes a circular loop at a speed of 200 ms⁻¹ with its wings banked at 45°. The radius of the loop is (g = 10 ms⁻²) *

(a) 4 km

(b) 5 km

(c) 8 km

(d) 12 km

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Answer 1

Answer:

Answer A is a correct option

Explanation:

Hope I am help you .

Answer 2

The radius of the loop is 4 km

Therefore, option (a) is correct.

Explanation:

Given:

Speed of the aircraft v = 200 m/s

Inclination of the wings θ = 45°

To find out:

The radius of the circular loop

Solution:

While navigating a circular path the tendency is to incline towards the centre of the circle

If $\theta$ is the inclination and $v$ is the speed of the vehicle Then

$\tan\theta=\frac{v^2}{gR}$

Where R is the radius of the circular path

Here,

$\theta=45^\circ$

$v=200$ m/s

Therefore,

$\tan 45^\circ=\frac{200^2}{10\times R}$

$\implies 1=\frac{4000}{R}$

$\implies R=4000$ m

or, $R=4$ km

Hope this answer is helpful.

Know More:

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