Question

An air parallel-plate capacitor has a plate area of
6x10 m and a plate separation of 3 mm. Calculate
its capacitance. If this capacitor is connected to a
100 V supply. What is the charge on each plate of the
capacitor?

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Answer 1

Hope this helps you...

Answer 2

Answer:

A parallel plate capacitor with an area is $60m^{2}$ and separated by a distance of 3 mm the capacitance is  $176*10^{-9}F$, the charge stored when a $100v$ battery connected is $176*10^{-7}C$

Explanation:

• The parallel plate capacitor is two parallel plates that are connected across a battery when the plates are charged an electric field will induce between them.

• The CAPACITANCE is the ability to store electric charge within the capacitor

• For a parallel plate capacitor with an area $A$ separated by a distance $d$ in free space, the capacitance is

                                  $C=\frac{\varepsilon _0\ A}{d}$

• The amount of charge $Q$ that is stored in a capacitor of capacitance $C$ when a battery of voltage $V$  connected

                                  $Q=CV$                    

from the question, we have

area of square plate $A=60m^{2}$

distance between two parallel plates $d=3mm=0.003m$

voltage  given $V=100v$

capacitance in free space $C=\frac{8.8*10^{-12} *60}{0.003} =176*10^{-9} F$

the charge stored in a plate $Q=176*10^{-9}*100=176*10^{-7}C$