Math, asked by AakashShende, 5 months ago

An air plane is flying 2000m above the surface of earth horizontaly the angle of elevation of plane on the earth is 60 degree after 10 seconds the angle angle of elevation from same point is 30 degree. Find the speed of plane?

Answers

Answered by kapilchavhan223

Answer:

it's FOR U R QUESTION

REF.Image

REF.Imagetan60

REF.Imagetan60 ∘

REF.Imagetan60 ∘ =

REF.Imagetan60 ∘ = x

REF.Imagetan60 ∘ = x3000

REF.Imagetan60 ∘ = x3000 3

REF.Imagetan60 ∘ = x3000 3 x=

REF.Imagetan60 ∘ = x3000 3 x= 3

REF.Imagetan60 ∘ = x3000 3 x= 3 3000

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000m

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ =

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000 3

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000 3 =9000m

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000 3 =9000mdistance covered = 9000- 3000

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000 3 =9000mdistance covered = 9000- 3000= 6000 m.

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000 3 =9000mdistance covered = 9000- 3000= 6000 m.speed =

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000 3 =9000mdistance covered = 9000- 3000= 6000 m.speed = 30

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000 3 =9000mdistance covered = 9000- 3000= 6000 m.speed = 306000

REF.Imagetan60 ∘ = x3000 3 x= 3 3000 3 =3000mtan30 ∘ = 1/ 3 3000 3 =9000mdistance covered = 9000- 3000= 6000 m.speed = 306000 =200m/s..

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