Question

an air rifle pellet of mass 2g is fired into a block of modeling clay mounted on a model railway track. The truck and modeling clay have a mass of 0.1 kg. The truck moves after the pellet hit the modeling clay with an initial velocity of 0.8m/s.
state the momentum of the pellet just before it hit the modeling clay

Answer 1

Explanation:

solution of the question is in photo

Answer 2

Answer:

40.8 m/s

Explanation:

Given:

Into a block of modelling clay installed on a model railroad track, a 2g air rifle pellet is fired. The mass of the truck and the modelling clay is 0.1 kg. After the pellet struck the modelling clay with an initial velocity of 0.8 m/s, the truck started to move.

To find:

The momentum of the pellet

Solution:

According to the principle of conservation of momentum , a system that is isolated maintains its same overall momentum. Momentum is the product of an item's mass and its speed, and it is also equivalent to the entire amount of force needed to bring an object to rest.

The momentum of the modelling clay and truck after the collision is

p=mv

p=(0.002 kg+0.1 kg)(0.8 m/s)

p=0.0816 m/s

Now for the initial velocity of the modeling clay

By using conservation of momentum

$p_1=p_2$

$(0.002kg)v_1p+(0.1kg)(0m/s)=(0.102kg)(0.8ms)\\v_p=\frac{(0.102kg)(0.8ms)}{( 0.0002kg)}\\v_1p=40.8m/s$

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