Question

An air rifle pellet of mass 2g is fired into a block of modelling clay mounted
on a model railway truck. The truck and modelling clay have a mass of
0.1 kg. The truck moves off after the pellet hits the modelling clay with an initial velocity of 0.8 m/s. Calculate the momentum of the modelling clay and truck just after the
collision.​

Answer 1

Answer:

By P = (M+m)v

=>P = (0.1+0.002) x 0.8

=>P = 8.16 x 10^-2 N-s

(2) Let the velocity of the pellet was u m/s before the collision,By the law of momentum conservation:-

=>m1u1+m2u2 = (m1+m2)v

=>0.002 x u + 0 = 8.16 x 10^-2

=>u = 40.80 m/s

Answer 2

Explanation:

P=mg sin θ+μmg cos θ)V

\large\sf { = (1000 × 9.8 × \frac {1}{ \sqrt {5}} + \frac {1}{ \sqrt{3}} ×1000×9.8 × \frac {2}{ \sqrt{5}}}=(1000×9.8×

5

1

+

3

1

×1000×9.8×

5

2

\large\rm { 36 × \frac {5}{18} = 94.4 × 10³ W}36×

18

5

=94.4×10³W

\large\rm { = 36 kilowatt }=36kilowatt