An airbus runs on a runway from rest. Its final velocity is 810Km/hr. The length of the runway is 1000m. Calculate the uniform acceleration of the air bus.
Answers
Given :
Initial velocity of the airbus : 0 m/s
Final velocity of the airbus : 810 km/hr
Distance : 1000 m
To find :
The uniform acceleration of the airbus.
Solution :
Firstly we have to convert km/hr to m/s
we know that,
» 1km/hr = 5/18km/hr
» 810km/hr = 810 × 5/18 = 225 m/s
Accerlation is the rate of change of velocity.
- It is a vector quantity having both magnitude as well as direction.
- SI unit of acceleration is metre per second square.
As we are provided with initial velocity, final velocity and distance we can use second equation of kinematics that is,
v² - u² = 2as
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- s denotes distance
by substituting all the given values in the formula,
➝ v² - u² = 2as
➝ (810)² - (0)² = 2(a)(1000)
➝ 656100 = 2000a
➝ a = 656100/2000
➝ a = 328.05
Thus, the acceleration of the air bus is 328.05 m/s².
Know more :
First equation of kinematics : v = u + at
Second equation of kinematics : s = ut + 1/2at²
Third equation of kinematics : v² - u² = 2as
Answer:-
- Initial velocity=u=0m/s
- Final velocity=810km/h
Convert it to m/s
- Distance=1000m
According to second equation of kinematics