Question

An airbus runs on runway from rest its final velocity is 810 kilometre per hour the length of the runway is 1000 calculate the uniform acceleration of the airbus

Answer 1

Answer:25.3125

Explanation:v²-u²=2as

225²-0²= 2000 a

a= 50625/200

= 25.3125

Answer 2

Concept:

• One-dimensional motion
• We need to know the kinematic equations of one-dimensional motion

Given:

• Airbus starts from rest, so initial velocity u = 0 m/s
• Final velocity = 810 km/h = 225 m/s
• Length of the runway s = 1000 m

Find:

• The acceleration of the Airbus

Solution:

We know the following kinematic equation to calculate the displacement.

v^2 = u^2 +2as

where s is the displacement, u is the initial velocity, v is the final velocity and a is the acceleration.

v = 225 m/s, u = 0 m/s, s = 1000 m

2as = v^2-u^2

a = (v^2-u^2)/2s

a = (225^2 -0)/2*1000

a = 50625/2000 = 25.3 m/s^2

The uniform acceleration of the airbus is 25.3 m/s^2

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