An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15°. What is the radius of the loop?
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Hii bae,
# Answer- 15 km
## Explaination-
# Given-
v = 720 km/h = 200 m/s
θ = 15°
# Solution-
For circular motion with inclination θ, we have
tanθ = v^2 / rg
Putting values,
tan15 = (200)^2 / (r×10)
r = 4000/0.268
r = 14925 m
r = 15 km
Radius of the loop is 15 km.
Hope that was useful..
# Answer- 15 km
## Explaination-
# Given-
v = 720 km/h = 200 m/s
θ = 15°
# Solution-
For circular motion with inclination θ, we have
tanθ = v^2 / rg
Putting values,
tan15 = (200)^2 / (r×10)
r = 4000/0.268
r = 14925 m
r = 15 km
Radius of the loop is 15 km.
Hope that was useful..
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