Question

An aircraft executes a horizontal loop of radius 1.00 km with steady speed of 900 km/h. Compare its centripetal acceleration with Acceleration due to gravity.

Answer 1

Hey friend,

# Answer- a = 62.5 m/s^2 = 6.38×g

# Given-
r = 1 km = 10^3 m
v = 900 km/h = 250 m/s

# Solution-
Acceleration of particle moving in centripetal motion is given by,
a = v^2/r
a = (250)^2/10^3
a = 62500/1000
a = 62.5 m/s^2

We know g = 9.8 m/s^2
a/g = 62.5/9.8
a/g = 6.38

Hence, centripetal acceleration here is 6.38 times larger than acceleration due to gravity.

Hope that helps you...

Answer 2

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Radius of the loop, r = 1 km = 1000 m

Speed of the aircraft,

v = 900 km/h= 900× 5/18 = 260m/s

Centripetal acceleration,

a(c) = v^2/ r

= (250)^2/1000

= 62.5 m/s^2

Acceleration due to gravity, g = 9.8 m/s2

a(c)/ g

=62.5/9.8

= 6.38

=> a(c)= 9.38 g

I hope, this will help you

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