Question

An aircraft executes a horizontal loop of radius 1km with a steady speed of 900km/h. What is the magnitude and direction of centripetal acceleration? Is it a constant vector?

Answer 1

HEY DEAR ...

Radius of the loop, r = 1 km = 1000 m
Speed of the aircraft, v = 900 km/h = 900 × 5 / 18  =  250 m/s
Centripetal acceleration, ac = v2 / r 
= (250)2 / 1000 = 62.5 ms-2
Acceleration due to gravity, g = 9.8 m/s2

ac / g = 62.5 / 9.8  =  6.38
ac = 6.38 g

HOPE , IT HELPS ...

Answer 2

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Radius of the loop, r = 1 km = 1000 m

Speed of the aircraft,

v = 900 km/h= 900× 5/18 = 260m/s

Centripetal acceleration,

a(c) = v^2/ r

= (250)^2/1000

= 62.5 m/s^2

Acceleration due to gravity, g = 9.8 m/s2

a(c)/ g

=62.5/9.8

= 6.38

=> a(c)= 9.38 g

I hope, this will help you

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