An aircraft flies 400km from point O on a bearing of 025 and then 700km on a baring of 080to arrive at B.how far north go O is B?
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Used the horizontal and vertical components of distances to find the solution.
(1)
400 km, 25
(1)
400 km, 25
Golda:
sorry the answer is incomplete. x = 400sin 25degrees = 169, y = 400cos25 degrees = 362.5 (2)
(2) 700 km, 80 degrees, x = 700sin80 degree = 689.4, 700cos80 degrees = 121.5. So how far north of O is B = 362.5 + 121.5 = 484 km.
Actually i had to click on the mathematical symbols but by mistake I clicked on send your answer. Sorry for the mistake.
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