Question

An aircraft flies a certain distance on a bearing of 135 degree and then twice the distance on a bearing of 225 degree .it's distance from the starting point is then 350 km.find the length of the first part of the journey.

Answer 1

Answer:

the length of the first part of the journey = X= 70√5 m

Step-by-step explanation:

Let the plane start at A and go to B which is 135° position

Let AB= X

From B let it go to C in a direction BC which at position 225°

therefore ∠ABC= 225-135= 90°

BC = 2X ( Given)

So in righ angle triangle ABC

AC^2= AB^2 + BC^2

350^2 = X^2+ (2X)^2

⇒X= 70*70*5

X = 70√5 m

the length of the first part of the journey = X= 70√5 m

Answer 2

Step-by-step explanation:

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