Question

an aircraft flies with a speed of 360 km per hour angle of elevation was 45 degree after
the angle was observed to be 30 determine it's height​

Answer 1

Answer:

Given that,

Speed of aircraft =360 km/h,

∴ Distance covered by the aircraft in 20 seconds =

(60×60)

(360×20)

=2 km

Consider

E as the fixed point on the ground,

CD as the position of AB in height of aircraft.

And take AB=CD=h.

In right △ARB

tanθ=

EB

AB

Substituting the values,

⇒tan45

o

=

EB

h

⇒1=

EB

h

⇒EB=h

Here,

ED=EB+BD=h+2

In right △CED

tan30

o

=

ED

CD

Substituting the values,

⇒

3

1

=

(h+2)

h

⇒

3

h=h+2

⇒1.732h−h=2

⇒0.732h=2

⇒h=

0.732

2

=2.732 km

⇒h=2732m.

Hence, height at which the aeroplane is flying is 2732 m