Question

An aircraft is flaying at a hesigh of 34000m above the ground. If angle subtended at a ground observation point by the aircraft position 10s apart and is 30°,then the speed of the air fraft is what​

Answer 1

$\huge{\underline{\underline{\mathbb{\red{ANSWER}}}}}$

In right angle triangle OAB,

tan30°

$= \frac{h}{x}$

we get

$x = \frac{h}{tan30}$

so,

$x = 3400 \sqrt{3} \\ = 5889 \: m$

Time taken t = 10.0 s

Thus the speed of the aircraft,

$v = \frac{x}{t}$

so,

$v = \frac{5889}{10.0} = 588.9 \: m \: per \: sec.$