Question

An aircraft is travelling along a runway at a velocity of 25m/s. It

accelerates at a rate of 4m/s 2 for a distance of 750m before taking off.

Calculate its take off speed.

Answer 1

Answer:

initial velocity (u)= 25m/s

let final velocity (v) be v

acceleration= 4m/s^2

distance travelled (s) = 750 m

now by the third equation of motion we have,

2as= v^2-u^2

2×4×750= v^2- (25)^2

v^2= 6000-625

v= √5375

v= 73.31(approx)

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