Question

. An aircraft is travelling at 150m/s for 1 minute and returns 200m/s in 45s . Calculate the average speed and average velocity.

Answer 1

Answer:

If both the starting and ending points are the same, then the net displacement is 0 m. Therefore Average Velocity is also 0 m/s.

Average Speed = Total Distance Travelled / Total Time taken

⇒ 150 m/s for 1 minute

⇒ 150 m/s for 60 seconds

⇒ Distance Covered = 150 × 60 = 9000 m

⇒ 200 m/s for 45 seconds

⇒ Distance Covered = 200 × 45 = 9000 m

Therefore Total Distance covered = 9000 + 9000 = 18,000

Total Time = 60 sec  + 45 sec = 105 sec

⇒ Average Speed = 18,000 m / 105 sec = 171.42 m/s

This is the required average speed.

Hope it helped !!

Answer 2

$\huge{\mathfrak{\red{\underline{Answer :- }}}}$

If both the starting and ending points are the same, then Average Velocity is also 0 m/s.

$\rule{200}{2}$

$\bf{\boxed{Average \:Speed = \frac{Total \: Distance \:Travelled}{Total \: Time \:Taken}}}$

______________[Put Values]

☆ Case 1

Distance Covered = 150 × 60 = 9000 m

$\rule{200}{2}$

☆ Case 2

Distance Covered = 200 × 45 = 9000 m

$\rule{200}{2}$

Total Distance covered = Case 1 + Case 2

= 9000 + 9000 = 18,000

Total Time = 60 sec  + 45 sec = 105 sec

$\rule{200}{2}$

$\bf{\boxed{Average \: Speed = \frac{Total \: Distance \:Travelled}{Total \: Time \:Taken}}}$

Average Speed = 18,000 m / 105 sec = 171.42 m/s

$\rule{200}{2}$