Question

An aircraft on its take off run has a steady acceleration of 3m/s².what velocity does the aircraft gain in 4s

Answer 1

Given:

Initial velocity ,u = 0

Acceleration ,a = 3m/s^2

Time,t = 4 sec

To Find:

velocity gained after 4 sec

Solution:

By using first equation of motion -

V=U+AT

V= 0+3×4

V= 0+12

V = 12 m

$\boxed{\boxed{\boxed{\mathbb{V=12m}}}}$