an aircraft travelling 600 km per hour accelerator study at 10 km per hour per second taking speed of sound as 11 CA 11000 km per hour at the aircraft altitude how long will take to reach the sound barrier
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u = 600 kmph
v = 11,000 kmph
a = 10 kmph / second
t = (v-u)/a = 10400/10 seconds
t = 52/3 minutes
v = 11,000 kmph
a = 10 kmph / second
t = (v-u)/a = 10400/10 seconds
t = 52/3 minutes
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Hi !
Initial velocity = u = 600 kmph
Final velocity = v = 11,000 km/hr
acceleration = a = 10 km/hr / sec
a = v-u/t
t = (v-u)/a
= 10400/10
= 52/3 minutes
Initial velocity = u = 600 kmph
Final velocity = v = 11,000 km/hr
acceleration = a = 10 km/hr / sec
a = v-u/t
t = (v-u)/a
= 10400/10
= 52/3 minutes
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