an aircraft travelling at 600 kilometre per hour accelerates steadily at 10 kilometre per hour per second taking the speed of sound of 1100 km per hour at the aircraft attitude how long will it take to reach the sound barrier
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Answer:
Explanation:
The aircraft has to sound barrier ,i.e.
v=1100km/h=1100×5/18=2750/9 m/s
u=600km/h=600×5/18=1500/9 m/s
The acceleration of the aircraft 10km/h per second
a=10km/h/s=10×5/18 m/s/s= 25/9m/s^2
Using first equation of motion
v=u + at
2750/9=1500/9+ 25t/9
2750=1500+25t
27500-1500/25=1250/25
= 50s
hence the aircraft will cross the sound barrier in 50s.
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