Question

An aircraft travelling at 600 km h accelerates steadily at 10 km h per second taking the speedof sound as 1100km/hat the aircraft's altitudehow long will it take toreach sound's barrier

Answer 1

Explanation:

The aircraft has to sound barrier ,i.e.

v=1100km/h=1100×5/18=2750/9 m/s

u=600km/h=600×5/18=1500/9 m/s

The acceleration of the aircraft 10km/h per second

a=10km/h/s=10×5/18 m/s/s= 25/9m/s^2

Using first equation of motion

v=u + at

2750/9=1500/9+ 25t/9

2750=1500+25t

27500-1500/25=1250/25

= 50s

hence the aircraft will cross the sound barrier in 50s.