An aircraft travelling at 600 km/h accelerates steadily at 10 km/h per second. Taking the speed of sound as 1100 km/h at the aircraft's altitude,how long will it take to reach the sound barrier ???
⊙PLEASE if rammu5 answer it
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Hey dear !!
Here is your answer !!
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♦♦ Given ->
Initial velocity - 600 km/h
Final velocity - 1100 km/h
Let us take u as initial velocity and v as final velocity.
Acceleration-10 km/h /s
♦♦ Solution ->
Now change km/h to m/s
Hence,
u=166.66 m/s
v=305.55 m/s
a=2.78 m/s*s=2.78 m/s^2
Using first equation of the motion which is
v=u+at
Put values in the equation
305.55=166.66+2.78(t)
t=(305.55-166.66)/2.78
t=138.89/2.78
t=13889*100/278*100
t=13889/278
t=49.9s
which is near value to 50s
Hence the time is 50 seconds to reach the sound barrier.
Hope it is satisfactory :-)
____________________________________________
Here is your answer !!
____________________________________________
♦♦ Given ->
Initial velocity - 600 km/h
Final velocity - 1100 km/h
Let us take u as initial velocity and v as final velocity.
Acceleration-10 km/h /s
♦♦ Solution ->
Now change km/h to m/s
Hence,
u=166.66 m/s
v=305.55 m/s
a=2.78 m/s*s=2.78 m/s^2
Using first equation of the motion which is
v=u+at
Put values in the equation
305.55=166.66+2.78(t)
t=(305.55-166.66)/2.78
t=138.89/2.78
t=13889*100/278*100
t=13889/278
t=49.9s
which is near value to 50s
Hence the time is 50 seconds to reach the sound barrier.
Hope it is satisfactory :-)
____________________________________________
Anonymous:
so!
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