an aircraft travelling at 600 km per hour accelerates steadily at 10 km per hour per second. taking the speed of sound as 1100 km per hour at the aircraft altitude how long will it take to reach the sound barrier
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Answered by
469
Here the initial velocity of the air craft = 600 km/h
Acceleration a = 10 km/h/s
Final velocity = velocity of sound at aircraft’s altitude v = 1100 km/h
We have v = u + at. Therefore t = (v – u)/a = [(1100 – 600) km/h ]/ (10 km/h/s) = 50 s.
This is the time taken to reach the sound barrier
Acceleration a = 10 km/h/s
Final velocity = velocity of sound at aircraft’s altitude v = 1100 km/h
We have v = u + at. Therefore t = (v – u)/a = [(1100 – 600) km/h ]/ (10 km/h/s) = 50 s.
This is the time taken to reach the sound barrier
THETIGGER:
hi
Answered by
178
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speed of sound = 1100 km/hr
v = u + a t
t = (v - u) / a = (1100 - 600 ) / 10 = 50 s
I hope, this will help you
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