Question

an aircraft travelling at 600 km per hour accelerates steadily at 100 km per hour ,per second taking the speed of sound as 1100 km per hour at the aircraft altitude how long will it take to reach the sound barrier

Answer 1

The aircraft has to sound barrier ,i.e.
v=1100km/h=1100×5/18=2750/9 m/s
u=600km/h=600×5/18=1500/9 m/s

The acceleration of the aircraft 10km/h per second
a=10km/h/s=10×5/18 m/s/s= 25/9m/s^2

Using first equation of motion
v=u + at
2750/9=1500/9+ 25t/9
2750=1500+25t
27500-1500/25=1250/25
= 50s

Answer 2

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$\huge\mathfrak\red{hello...frd\:swigy\:here}$

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speed of sound = 1100 km/hr

v = u + a t

t = (v - u) / a = (1100 - 600 ) / 10 = 50 s

I hope, this will help you

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