Question

an aircraft travelling at600km/h accelerates steadily at 10km/h per second. taking the speed of sound as 1100km/h at the aircraft's altitude how long will it take to reach the sound barrier

Answer 1

the aircraft has to cross sound barrier ,i.e.
v=1100 km/h =1100 x 5/18= 2750/9 m/s

u=600 km/h = 600 x 5/18 = 1500/9 m/s

the acceleration of the aircraft is 10 km/h per second
a= 10 km/h/s = 10 x 5/18 m/s/s = 25/9 m/s^2

using first equation of motion
v = u+at 
2750/9= 1500/9 + 25t/9
2750 = 1500 + 25 t
2750 - 1500 / 25 = 1250/25
= 50s
hence the aircraft will cross the sound barrier in 50 secs

Hope this helps you

Answer 2

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speed of sound = 1100 km/hr

v = u + a t

t = (v - u) / a = (1100 - 600 ) / 10 = 50 hours

I hope, this will help you

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