Question

an aircraft travellung at 600km/hr acclerates at 10km/hr per second taking speed of sound barrier 1100 km/hr how long will it take to reach sound barrier

Answer 1

Your answer ..

Aircraft has to reach sound barrier
it means it's final velocity (v) is = 1100 km/h
=>1100*5/18=2750/9 m/s

Initial velocity (u)=600 km/h
=>600*5/18=1500/9 m/s

Acceleration is 10 km/hr per second
(a)=>10*5/18=25/9

Now, Use Newton's 1st equation of motion.

v=u+at
2750/9=1500/9+25/9*t
2750/9=1500+25/9*t
2750=1500+25t
25t=2750-1500
t=1250/25
t=50s

$\bold{it\:will\:take\:50\:sec\: to \:cross\:the\:sound\:barrier}$

Answer 2

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speed of sound = 1100 km/hr

v = u + a t

t = (v - u) / a = (1100 - 600 ) / 10 = 50 s

I hope, this will help you

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