Question

An aircraft turn along circular path of radius 600m with the speed 300m/s. Find time taken to complete 1/4th of circular path

Answer 1

It's simple… observe the question, the question states “rate of velocity=2 m/s” i.e. accelaration in tangential direction which is now =2 m/s^2.

Now since a body in circular path has two components of accelaration i.e. radial (towards centre) and tangential. We already have the tangential.

For the radial accelaration:

A(r) = V^2÷R = 30^2÷500 = 900÷500 = 1.8 rad/sec^2.

Since these two Vectors have an angle of 90° b/w them, the net Vectorial accelaration becomes:

(A(t)^2 +A(r)^2)^1÷2 (because cos 90°=0)

=√7.24 ≈ 2.7 m/s^2

Answer 2

hey mate!

circumference of circle = distance covered

= 2*pi*r = 1200pi

now ,

for 1/4th path
distance covered = 1200pi/4

= 300pi

speed given = 300m/sec

time taken = distance/speed

T = 300pi/300

= 3.14sec