Question

an aircraft was a take off velocity of 50 m s what length of the Runway in needed if the aircraft is average acceleration alog the ground is 2.5m/s​

Answer 1

Answer:

length of the runnway - 500m

Explanation:

given :

velocity - 50m/s

average accelaration - 2.5m/s

length - ?

according to the 3rd equation of motion :

V^2 - U^2 = 2aS

as according to the question given :

velocity = 50m/s , (V= 50m/s)

intial velocity (U) = 0

average acceleration = 2.5m/s

substituting values :

(50) ^2 - (0) ^2 = 2 X 2.5 X S

2500 - 0 = 5.0 X S

2500 = 5.0 X S

2500/5.0 = S

S = 500 m