An airplane (10000-kilogram) must reach a velocity of 60 m/s to take off. If the horizontal force exerted by the plane’s engine is 60 kiloNewton and neglecting other horizontal forces, what length of runway is needed?
Answers
Answer:
an airplane is (10000_100
velocity is=60m/s
engine=60
now
take p=I/v
formula
60+60=120
Answer:
The required length of the runway is 300 m.
Explanation:
Given,
The mass of an airplane (m) = 10,000 Kg
The final velocity of the plane (v) = 60 m/s
The horizontal force exerted by the plane's engine (F) =60 kilo N = 60,000 N.
To find,
The distance traveled by plane before it just reaches 60 m/s
Assumption,
Let the required length of the run-way be 's'.
Calculation,
From Newton's 2nd law:
F = ma
⇒ a = F/m
⇒ a = 60,000/10,000
⇒ a = 6 m/s
Now we know that the plane has started from the rest
⇒ The initial velocity of the plane(u) is equal to zero.
So, from equations of motion
v² - u² =2as
⇒ 60² - 0² = 2 × 6 × s
⇒ 3600 = 12 × s
⇒ s = 300 m
Therefore, the required length of the runway is 300 m.
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