Question

An airplane accelerated from rest at a rate of 5 m/s​ for 14 s. What was its final
velocity

Answer 1

Answer:

According to First equation of motion, final velocity is given as:

• v = u + at

Where, v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken by undergoing acceleration.

According to the question,

• u = 0 ( As it started from rest )
• a = 5 m/s²
• t = 14 seconds

Substituting in the equation we get,

⇒ v = u + at

⇒ v = 0 + 5 ( 14 )

⇒ v = 70 m/s

Hence the final velocity attained by the airplane at 14 seconds is 70 m/s.

Answer 2

Answer:

here is ur answer mate...!!

we know ...

accelaration= velocity/ time

5m/s=velocity/14s

70m/s is ur answer

70m/s is its final velocity

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