Question

An airplane accelerates down a runway at 3.20 m/s_2 for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff?​

Answer 1

Answer:

Distance is 1721.34m=1.72 km

Explanation:

Given data:

a=3.20 m/s^2

t=32.8 sec

u=0 m/s

We know that,

v=u+at

0+3.20*32.8

v=104.96 m/s

Now we know that,

S=ut+1/2at^2

=0*32.8+1/2*3.20*32.8*32.8

=0+1/2*3.20*1075.84

=0+3.20*537.92

S=1721.34 m