an airplane approaches the airport. At a certain time, the plane is 1020m high. Its angle of elevation measured from the airport is 20.5 degrees. How far is the plane from the nearest metre? ITS URGENT PLS HELP
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Answer:
2728.11m
Step-by-step explanation:
The height of the plane is 1020m
The airport makes an angle of elevation of 20.50° with the plane
The distance of the plane from the airport = ?
See attached document for better illustration of the position of the plane and airport
Using SOHCAHTOA,
tanΘ = opposite/ adjacent
θ = 20.50°
opposite = 1020m
adjacent = ? = x
Tanθ = opposite/ adjacent
Tan20.50 = 1020 / x
X = 1020 / tan20.50
X = 1020 / 0.37388
X = 2728.11m
The distance of the plane from the airport is 2728.11m
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