An airplane is at a location 800 miles due west of city X. Another airplane is at a distance of 1,200 miles southwest of city X. The angle at city X created by the paths of the two planes moving away from city X measures 60°.
What is the distance between the two airplanes to the nearest mile? Assume that the planes are flying at the same altitude.
A. 894 miles
B. 646 miles
C. 1,251 miles
D. 1,058 miles
Answers
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Step-by-step explanation:
It helps to draw this. From the drawing, the estimate is between 400 (they are the same direction) to 800, less than the distance either is from the city.
Law of cosines.
c^2=a^2+b^2-2abcos C
c^2=800^+1200^2-2(800)(1200)cos 30
=417231.22
c=sqrt (417231.22)=645.93 rounded to 646 miles.
B is the correct ans. Mark as brainliest please
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