An airplane is flying with velocity goms at an angle 23 avobe horizontal when the plane is likim directly above a dog Standing on the ground on the ground, A suitcase Ps A dropped out. Hlous far from og will the suitcase land. Ignore air resistance. [779 from deg?
Yeash he is
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Step-by-step explanation:
The suitcase moves in projectile motion. The initial velocity of the suitcase is equal to the velocity of the airplane.
To find the time, it takes to reach the ground
the y-component of the velocity
v0y=v0sin23∘
The acceleration
ay=−9.8m/s2
since +y is taken to be upward.
Now, the vertical distance from the plane to the dog s=114m.
Putting these values in the equation of motion to find the time t, we have
114=90sin23∘+12×(−9.8)×t2
This gives,
t=9.60s
TThe distance the suitcase travels horizontally is
v0xt=(v0cos23∘)t=795m
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