Question

an airplane moving horizontally with a speed of 1
80km/h drops a food packet while flying at a height of 490m .The horizontal range of food packet is

Answer 1

Sea the picture
Horizontal range=50*10=500m

Answer 2

As the Horizontal Component of the plane and food packet are equal:

Horizontal Velocity of Food Packet = 80km/h = 50m/s

Therefore Horizontal distance is, s = u*t

s = 22.23*t

we can find "t" using the vertical component

if vertical height = 490m, vertical acceleration downwards = $10ms^{-2}$

so using equations of linear motion we can deduce that

s=ut+0.5at*t

490=0*t+0.5*10*t*t

490/5=$t^{2}$

$\sqrt{98} = t^{2}$

9.9=t

10=t

Then substitute t=-10 to the 1st equation:

s=u*t

s=50*10

s=500m

So as shown above the horizontal range of the food packet is 500m