Question

an airplane moving horizontally with a speed of 180 kmph drops a food packet while flying at a height of 490 m. the horizontal range of a food packet is

Answer 1

♠️motion along vertical

here u=0; y=490m; a=g=9.8m/s²

y=ut+1/2at²

490=0*t+1/2*9.8*t²

4.9t²=490

t²=100

t=10sec

♠️for motion along horizontal

here u=180km/h=180(1000m)(3600sec)-¹

so initial velocity in m/s is 50/s

♠️ therefore horizontal range of the food packet is

x=u*t

x=50*10

x=500m