An airplane pilot sets a compass course due west and maintains an air speed of 240 km/h
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I think the question is incomplete.
Here I have written the whole question:
an airplane pilot sets a compass course due west and maintains an air speed of 240 km/h. after flying for 1/2 h, he finds himself over a town that is 150 km west and 40 km south of his starting point. the wind velocity :
d^2=(150)^2+(40)^2
=22500+1600
=24100 km^2
d=√24100
=155 km
θ=tan−1(40/150)
=tan−10.2667
=15°
Velocity of pilot with respect to ground (v→1) is given by
v→1=155/0.5=310 km h−1
Let v→2 be the velocity of air and Let v→3 be the velocity of wind with respect to ground.
Now,
Using cosine law we have
v→3^2=v→1^2+v→2^2−2v→1v→2cos15°
=(240)^2+(310)^2−2(210)(310)(0.9659)
=57600+96100−143730
=9970
⇒v→3 =100 km h−1
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