Physics, asked by Ramees123, 2 months ago

An airplane takes 2 minutes to travel the short distance between airports on two islands. 3 The graph shows how the speed of the aeroplane changes as it
• Takes off
• flies across the sea
• lands on the other island.

When it flies across the sea it travels with a constant speed. Use the graph to answer the following questions.
a. Calculate the acceleration at the start of the journey.
b. Calculate the total distance that the aeroplane travels.

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Answers

Answered by vedikadixit52
0

Answer:

The acceleration at the start of the journey is 2.5 m/s^2. The airplane travels a total distance of 31,000 meters or 31 kilometers during the journey.

Explanation:

a. To calculate the acceleration at the start of the journey, we need to look at the slope of the velocity-time graph during the takeoff phase. From the graph, we can see that the velocity increases from 0 m/s to 50 m/s in 20 seconds. Therefore, the acceleration can be calculated using the following formula:

acceleration = change in velocity/time taken

= (50 m/s - 0 m/s) / 20 s

= 2.5 m/s^2

So, the acceleration at the start of the journey is 2.5 m/s^2.

b. To calculate the total distance that the airplane travels, we need to find the area under the velocity-time graph. We can break the journey into three phases: takeoff, flight across the sea, and landing.

During the takeoff phase, the area under the velocity-time graph is given by the formula for the area of a triangle:

area = 1/2 x base x height

= 1/2 x 20 s x 50 m/s

= 500 m

During the flight across the sea, the velocity is constant at 500 m/s, so the distance traveled can be calculated using the formula:

distance = speed x time

= 500 m/s x 60 s

= 30,000 m

During the landing phase, the area under the velocity-time graph is also given by the formula for the area of a triangle:

area = 1/2 x base x height

= 1/2 x 20 s x 50 m/s

= 500 m

Therefore, the total distance that the airplane travels is:

total distance = distance during takeoff + distance during flight + distance during landing

= 500 m + 30,000 m + 500 m

= 31,000 m

So, the airplane travels a total distance of 31,000 meters or 31 kilometers during the journey.

To know more about the concept please go through the links:

https://brainly.in/question/9415862

https://brainly.in/question/34468607

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